Answer:
[tex]\huge\boxed{\dfrac{3}{2}=1\dfrac{1}{2}}[/tex]
Step-by-step explanation:
PEMDAS
P Parentheses first
E Exponents
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
[tex]\dfrac{5}{4}+4\cdot\left(\dfrac{3}{4}-\dfrac{1}{2}\right)^2=\dfrac{5}{4}+4\cdot\left(\dfrac{3}{4}-\dfrac{1\cdot2}{2\cdot2}\right)^2=\dfrac{5}{4}+4\cdot\left(\dfrac{3}{4}-\dfrac{2}{4}\right)^2\\\\=\dfrac{5}{4}+4\cdot\left(\dfrac{3-2}{4}\right)^2=\dfrac{5}{4}+4\cdot\left(\dfrac{1}{4}\right)^2=\dfrac{5}{4}+4\cdot\dfrac{1}{16}=\dfrac{5}{4}+\dfrac{4}{16}\\\\=\dfrac{5}{4}+\dfrac{1}{4}=\dfrac{5+1}{4}=\dfrac{6}{4}=\dfrac{6:2}{4:2}=\dfrac{3}{2}=1\dfrac{1}{2}[/tex]
