Question

If you plot and connect these points P1(3,2) and P2(6,8) , what figure is Formed? What is the Direction?

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Answer 1

Answer:

Please check the explanation.

Step-by-step explanation:

Given the points

• P1(3, 2)

• P2(6, 8)

When we plot P1(3, 2) and P2(6, 8), we determine the line segment P1P2.

The direction of the segment is from P1 to P2.

Determining the length of the segment P1P2.

$\:l=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

  $=\sqrt{\left(6-3\right)^2+\left(8-2\right)^2}$

  $=\sqrt{3^2+6^2}$

  $=\sqrt{45}$

  $=\sqrt{5}\sqrt{3^2}$

  $=3\sqrt{5}$

Thus, the length of the segment is:

$\:\:\:l=3\sqrt{5}$

Determining the equation of a line containing the segment P1P2

Given the points

• P1(3, 2)

• P2(6, 8)

Finding the slope between P1(3, 2) and P2(6, 8)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(3,\:2\right),\:\left(x_2,\:y_2\right)=\left(6,\:8\right)$

$m=\frac{8-2}{6-3}$

$m=2$

Using the line point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

substituting the values m = 2 and the point (3, 2)

$y-2=2\left(x-3\right)$

Add 2 to both sides

$y-2+2=2\left(x-3\right)+2$

$y=2x-4$

Thus, the equation of a line containing the line segment P1P2 is:

$y=2x-4$