0.0157 g Au
Chemistry
Atomic Structure
Math
Pre-Algebra
Order of Operations: BPEMDAS
Step 1: Define
3.113 g Au
Step 2: Identify Conversions
Molar Mass of Au - 197.87 g/mol
Step 3: Convert
[tex]3.113 \ g \ Au(\frac{1 \ mol \ Au}{197.87 \ g \ Au} )[/tex] = 0.015733 g Au
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
0.015733 g Au ≈ 0.0157 g Au