Question

2. Dilute hydrochloric acid reacts with zinc to form zinc chloride and hydrogen.
(a) Find the volume of dilute hydrochloric acid of concentration 0.25 mol/dm^3 required to
react with 13 g of zinc.

(b) What is the volume of hydrogen formed at r.t.p.?
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Answer 1

Step-by-step explanation:

Zn + 2HCl => ZnCl2 + H2

Moles of Zn = 13g / (65.38g/mol) = 0.198mol

Volume of HCl = 0.396mol / (0.25mol/dm³) = 1.58dm³.

Volume of H2 = 0.198mol * (22.4dm³/mol) = 4.43dm³.