Answer:
The correct answer is "24 V".
Explanation:
The given values are:
Current,
I = 0.50 A
Resistance,
R = 12 W
As we know,
⇒ [tex]I = 0.5\times (\frac{E}{2R})[/tex]
On substituting the given values, we get
⇒ [tex]0.5= (\frac{E}{4\times 12} )[/tex]
⇒ [tex]0.5= (\frac{E}{48} )[/tex]
⇒ [tex]E=24 \ V[/tex]
