Question

let 'm' be mid value of class and 'L' be upper limit in frequency table. The lower limit of class is ? Please prove and answer ​

Answer 1

Answer:

Lower Limit = 2m-L

Step-by-step explanation:

Given that,

The mid value of class = m

Upper limit in the frequency table = L

We need to find the lower limit of the class.

The mid value of a class is given by :

$\text{mid-value}=\dfrac{\text{lower limit + upper limit}}{2}\\\\m=\dfrac{L+\text{lower limit}}{2}\\\\2m=L+\text{lower limit}\\\\\text{lower limit}=2m-L$

Hence, the lower limit of the class is 2m-L.