Complete Question:
To rationalize the denominator of 2√10/3√11 , you should multiply the expression by which fraction?
Answer:
Multiply by [tex]\frac{\sqrt{11}}{\sqrt{11}}[/tex]
Step-by-step explanation:
Given
[tex]\frac{2\sqrt{10}}{3\sqrt{11}}[/tex]
Required
To rationalize
To do this, we simply multiply the expression by the fraction of [tex]\frac{\sqrt{11}}{\sqrt{11}}[/tex]
This gives:
[tex]\frac{2\sqrt{10}}{3\sqrt{11}} * \frac{\sqrt{11}}{\sqrt{11}}[/tex]
[tex]\frac{2\sqrt{10 * 11}}{3\sqrt{11 * 11}}[/tex]
[tex]\frac{2\sqrt{110}}{3\sqrt{121}}[/tex]
Express [tex]\sqrt{121[/tex] as 11
[tex]\frac{2\sqrt{110}}{3*11}[/tex]
[tex]\frac{2\sqrt{110}}{33}[/tex]
Hence:
[tex]\frac{2\sqrt{10}}{3\sqrt{11}}[/tex] = [tex]\frac{2\sqrt{110}}{33}[/tex]