Question

Please help. 40 points + brainliest

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1. Solve for q:

√3q + 2 = √5

2. solve for d:

4d + 1 = √3

3. Solve for m:

m/√3 - 11 = 4

Answer 1

Answer:

1) q = (sq rt 15 - 2) / 3

2) d = (sq rt 3 - 1) / 4

3) m = 15 * sq rt 3

Step-by-step explanation:

Answer 2

1.√3q + 2 = √5

we bring to the power of 2 each element

(√3q)^2+2^2=√5^2

3q+4=5

3q=4-5

q=1/3

2.

4d+1=√3

we do the same thing

16d^2+1=3

16d^2=2

d^2=2/16

d^2=1/8

d=√1/√8

3.

m/√3 -11=4

first we rationalise by multiplying the first fraction with √3

m√3 /3-11=4

now we can bring to the power of 2

3m^2/9-121=16

3m^2/9=137

m^2/3=137

m^2=411

m=√411