Question

Find rhe x- and y- intercerpts of the following relationships.(There may be more then one)
$3x^{2} + 2y^2 = 24$

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given

3x² + 2y² = 24

To find the x- intercepts , let y = 0 in the equation and solve for x

3x² + 2(0)² = 24, that is

3x² = 24 ( divide both sides by 3 )

x² = 8 ( take the square root of both sides )

x = ± $\sqrt{8}$ = ± 2$\sqrt{2}$ ← x- intercepts

To find the y- intercepts. let x = 0 in the equation and solve for y

3(0)² + 2y² = 24 , that is

2y² = 24 ( divide both sides by 2 )

y² = 12 ( take the square root of both sides )

y = ± $\sqrt{12}$ = ± 2$\sqrt{3}$ ← y- intercepts