Question

if x= (4/5)^-2 divided by (1/4)^2,find the value of x^-1
can u plz telll the ans

Answer 1

Answer:

$\displaystyle x^{-1}=\frac{1}{25}$

Step-by-step explanation:

The value of x is given:

$\displaystyle x= \frac{(4/5)^{-2}}{(1/4)^2}$

We need to find:

$\displaystyle x^{-1}=\frac{1}{x}=\frac{\frac{1}{4}^2}{\frac{4}{5}^{-2}}$

Operating:

$\displaystyle x^{-1}=\frac{1}{4}^2*\frac{5}{4}^{-2}$

Squaring:

$\displaystyle x^{-1}=\frac{1}{16}*\frac{16}{25}$

Multiplying:

$\mathbf{\displaystyle x^{-1}=\frac{1}{25}}$