help me please ^^ much appreciated

Answer:
C
Step-by-step explanation:
Using the sine ratio in the right triangle.
sinC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{16}{28}[/tex] , thus
∠ C = [tex]sin^{-1}[/tex] ([tex]\frac{16}{28}[/tex] ) ≈ 34.85° ( to 2 dec. places )