I need some help please

Answer:
Switch x and y.
[tex]\frac{1}{8} (x-4)^{3}[/tex]
Step-by-step explanation:
Switch the x and y, so the equation would read as:
[tex]x = \sqrt[3]{8y} +4[/tex]
Then solve for y.
[tex]x = \sqrt[3]{8y} + 4\\\\\\x - 4 = \sqrt[3]{8y} \\\\\\(x-4)^{3} = 8y\\\\\\\\\\\frac{1}{8} (x-4)^{3}[/tex]
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