Question

A 2.3 kg mass oscillates back and forth from the end of a spring of spring constant 120 N/m. Depending on that x max =0.7 calculate the total energy

Answer 1

Answer:

42.69J

Explanation:

The question is not complete, here the complete one

A 2.3 kg mass oscillates back and forth from the end of a spring of spring constant 120 N/m. Depending on that x max =0.7 calculate the total energy

and it velocity vx= -3.4m/s

Step one:

given

mass m= 2.3kg

spring constant k= 120 N/m

x= 0.7m

vx=-3.4m/s

Step two:

The expression for the total energy is

$Energy= 1/2mv^2 + 1/2Kx^2$

substituting we have

$Energy= 1/2*2.3*3.4^2+1/2*120*0.7^2$

$Energy= 13.29+29.4\\\\Energy=42.69J$