For the following equation: 2x^2 -3x + 7 = 0
(1) Calculate the discriminant
(2) Determine the number and type of solutions
(3) Use the quadratic formula to solve

Respuesta :

Answer:

Part 1)

[tex]\Delta=-47[/tex]

Part 2)

Since our discriminant is negative, we will have two complex (imaginary) solutions.

Part 3)

[tex]\displaystyle x_1=\frac{3}{4}+\frac{\sqrt{47}}{4}i\text{ and } x_2=\frac{3}{4}-\frac{\sqrt{47}}{4}i[/tex]

Step-by-step explanation:

We have the equation:

[tex]2x^2-3x+7=0[/tex]

Labelling our coefficients, we see that:

[tex]a=2, b=-3, \text{ and } c=7[/tex]

Part 1)

The discriminant (symbolized as Δ) is given by the formula:

[tex]\displaystyle \Delta=b^2-4ac[/tex]

So, the value of our discriminant is:

[tex]\displaystyle \Delta&=(-3)^2-4(2)(7)[/tex]

Evaluate:

[tex]\Delta=9-56=-47[/tex]

Part 2)

Remember the guidelines for the discriminant:

  • If Δ>0 (the discriminant is positive), then our equation has two real solutions.
  • If Δ<0 (the discriminant is negative), then our equation has two complex solutions (imaginary).
  • If Δ=0 (the discriminant is 0), then our equation has exactly one real root.

Since our discriminant is a negative value, we will have two complex (imaginary) roots.

Part C)

The quadratic formula is given by:

[tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

By substitution:

[tex]\displaystyle x=\frac{-(-3)\pm\sqrt{(-3)^2-4(2)(7)}}{2(2)}[/tex]

Evaluate:

[tex]\displaystyle x=\frac{3\pm\sqrt{-47}}{4}[/tex]

Simplify the square root:

[tex]\sqrt{-47}=\sqrt{-1\cdot47}=i\sqrt{47}[/tex]

Therefore:

[tex]\displaystyle x=\frac{3\pm i\sqrt{47}}{4}[/tex]

Hence, our two zeros are:

[tex]\displaystyle x_1=\frac{3+i\sqrt{47}}{4}\text{ and } x_2=\frac{3-i\sqrt{47}}{4}[/tex]

And in standard form:

[tex]\displaystyle x_1=\frac{3}{4}+\frac{\sqrt{47}}{4}i\text{ and } x_2=\frac{3}{4}-\frac{\sqrt{47}}{4}i[/tex]

Answer:

the discriminant is b squared - 4 (a) (c) where a = 2, b = -3, and c = 7

after plugging in, the discrimimant is -47

if the discriminant is negative then it has no 'real' roots (the graph will not intersect the x-axis) but it has 2 solutions:  (3+47i)/2 and (3-47i)/2 where 47i equals the square root of negative 47

Step-by-step explanation:

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