Respuesta :
Answer:
Part 1)
[tex]\Delta=-47[/tex]
Part 2)
Since our discriminant is negative, we will have two complex (imaginary) solutions.
Part 3)
[tex]\displaystyle x_1=\frac{3}{4}+\frac{\sqrt{47}}{4}i\text{ and } x_2=\frac{3}{4}-\frac{\sqrt{47}}{4}i[/tex]
Step-by-step explanation:
We have the equation:
[tex]2x^2-3x+7=0[/tex]
Labelling our coefficients, we see that:
[tex]a=2, b=-3, \text{ and } c=7[/tex]
Part 1)
The discriminant (symbolized as Δ) is given by the formula:
[tex]\displaystyle \Delta=b^2-4ac[/tex]
So, the value of our discriminant is:
[tex]\displaystyle \Delta&=(-3)^2-4(2)(7)[/tex]
Evaluate:
[tex]\Delta=9-56=-47[/tex]
Part 2)
Remember the guidelines for the discriminant:
- If Δ>0 (the discriminant is positive), then our equation has two real solutions.
- If Δ<0 (the discriminant is negative), then our equation has two complex solutions (imaginary).
- If Δ=0 (the discriminant is 0), then our equation has exactly one real root.
Since our discriminant is a negative value, we will have two complex (imaginary) roots.
Part C)
The quadratic formula is given by:
[tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
By substitution:
[tex]\displaystyle x=\frac{-(-3)\pm\sqrt{(-3)^2-4(2)(7)}}{2(2)}[/tex]
Evaluate:
[tex]\displaystyle x=\frac{3\pm\sqrt{-47}}{4}[/tex]
Simplify the square root:
[tex]\sqrt{-47}=\sqrt{-1\cdot47}=i\sqrt{47}[/tex]
Therefore:
[tex]\displaystyle x=\frac{3\pm i\sqrt{47}}{4}[/tex]
Hence, our two zeros are:
[tex]\displaystyle x_1=\frac{3+i\sqrt{47}}{4}\text{ and } x_2=\frac{3-i\sqrt{47}}{4}[/tex]
And in standard form:
[tex]\displaystyle x_1=\frac{3}{4}+\frac{\sqrt{47}}{4}i\text{ and } x_2=\frac{3}{4}-\frac{\sqrt{47}}{4}i[/tex]
Answer:
the discriminant is b squared - 4 (a) (c) where a = 2, b = -3, and c = 7
after plugging in, the discrimimant is -47
if the discriminant is negative then it has no 'real' roots (the graph will not intersect the x-axis) but it has 2 solutions: (3+47i)/2 and (3-47i)/2 where 47i equals the square root of negative 47
Step-by-step explanation: