There is a 90 kg woman attached at the end of a bungee cord (k = 35 N/m) that is experiencing simple harmonic motion. How long does it take the woman to complete one cycle?

Respuesta :

Answer:

The value is [tex]T =10.1 \ s[/tex]

Explanation:

From the question we are told that

    The mass of the woman is  [tex]m = 90 \ kg[/tex]  

    The spring constant of the bungee cord is  [tex]k = 35 \ N/ m[/tex]

Generally the period of the oscillation (i,e time taken to complete on  cycle ) is mathematically represented as

            [tex]T = 2 \pi * \sqrt{ \frac{m}{k} }[/tex]

=>      [tex]T = 2 * 3.142 * \sqrt{ \frac{90 }{ 35} }[/tex]

=>      [tex]T =10.1 \ s[/tex]

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