Question

A pyrotechnician plans for two fireworks to explode together at the same height in the air. They travel at speeds shown below. Firework B is launched 0.25 s before Firework A. How many seconds after Firework B launches will both fireworks​ explode?

Firework A = 360 ft/s

Firework B = 320 ft/s

Answer 1

Answer:

A:360-0.25= 359.75 s

B:320-0.25=319.75 s

359.75-319.75=40s

Step-by-step explanation:

40 seconds is the answer if you use subtraction.