Answer:
See Explanation
Step-by-step explanation:
[tex]\overline{FH} \: bisects \: \angle EHG... (given) \\\\
In\: \triangle FEH \: and\:\triangle FGH\\\\
\angle FEH\cong\angle FGH.. (given) \\\\
\angle EHF\cong\angle GHF\\(\because \overline{FH} \: bisects \: \angle EHG) \\\\
\overline{FH} \cong \overline{FH}...(common)\\ \\
\therefore \triangle FEH \cong\triangle FGH(AAS \: Postulate)
[/tex]
