Answer:
79,920 different ways
Step-by-step explanation:
Combination has to do with selection:
If we are to select 3 teachers from a pool of 10 teachers to form a committee, this can be done in 10C3 number of ways.
10C3 = 10!/(10-3)!3!
10C3 = 10!/7!3!
10C3 = 10*9*8*7!/7!3!
10C3 = 10*9*8/3*2
10C3 = 720/6
10C3 = 120 ways
Similarly, selecting five 2 students from a pool of 37 students to form a committee, this can be done in 37C2 difference ways;
37C2 = 37!/(37-2)!2!
37C2 = 37!/35!2!
37C2 = 37*36*35!/35!*2
37C2 = 37*36/2
37C2 = 37 * 18
37C2 = 666 ways
Hence the total number of ways that the 5 committees can be selected is expressed as 10C3 * 37C3 = 120 * 666
120 * 666 = 79,920 ways
