Respuesta :
Answer:1296 if I’m not wrong please
Step-by-step explanation:
Step-by-step explanation:
Appropriate Question :
- The area of square field is 5184m². Find the area of the rectangular field whose perimeter is equal to the perimeter of square field and whose length is twice of its breadth.
[tex] \frak{\red{Given}} \begin{cases} & \sf {Area\ of\ the\ square\ field\ is\ 5184m^2.} \\ & \sf {Perimeter\ of\ rectangular\ field\ is\ equal\ to\ perimeter\ of\ square\ field.} \\ & \sf {Length\ of\ the\ rectangular\ field\ is\ twice\ to\ the\ breadth\ of\ the\ square\ field.} \end{cases}[/tex]
Need to find : We have to find the area of the rectangular field.
- We are given the area of the square field, that is 5184m². So firstly, let us find out the side of the square field.
Let the side of the square field be a.
SidE :-
- a² = 5184m²
- a = √5184m
- a = 2 × 2 × 2 × 9
- a = 72m
∴ Hence, the side of the square field is 72m. Now, let's find out the perimeter of square.
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[tex] \red \bigstar \sf{\underline{Finding\ perimeter\ of\ square:-}} [/tex]
[tex] \sf \dashrightarrow {Perimeter\ of\ square\ =\ 4a} \\ \\ \sf \dashrightarrow {4 \times 72} \\ \\ \dashrightarrow {\underline{\boxed{\purple{\frak{288m}}}}} [/tex]
∴ Hence, the perimeter of the square field is 288m. Now, let us find out the length and breadth of the rectangular field.
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- Since, it is given that perimeter of the rectangular field is equal to the perimeter of square field. Also, the length of the rectangular field is twice the breadth of the square field.
[tex] \sf : \implies {Perimeter\ of\ rectangle\ =\ Perimeter\ of\ square} \\ \\ \sf : \implies {2(l\ +\ b)\ =\ 288} \\ \\ \sf : \implies {2(2b\ +\ b)\ =\ 288} \\ \\ \sf : \implies {4b\ +\ 2b\ =\ 288} \\ \\ \sf : \implies {6b\ =\ 288} \\ \\ \sf : \implies {b\ =\ \dfrac{\cancel{288}}{\cancel{6}}} \\ \\ : \implies {\underline{\boxed{\purple{\frak{b\ =\ 48m}}}}} [/tex]
∴ Hence, breadth of the rectangular field is 48m. Now, let's find out the length of the rectangular field.
LengtH :-
- 2(48)
- 2 × 48
- 96m
∴ Hence, the length of the rectangular field is 96m. Now, let's find out the area of the rectangular field.
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[tex] \red \bigstar \sf{\underline{Finding\ area\ of\ the\ rectangular\ field:-}} [/tex]
[tex] \sf : \implies {Area\ of\ rectangle\ =\ l \times b} \\ \\ \sf : \implies {Area\ of\ rectangle\ =\ 96 \times 48} \\ \\ : \implies {\underbrace{\boxed{\pink{\frak{Area\ of\ rectangle\ =\ 4608m^2}}}}_{\sf \blue{\tiny{Area\ of\ the\ field}}}} [/tex]
∴ Hence, area of the rectangular field is 4608m².