Question

What is the value of x for which (8-x)^2=x^2

Answer 1

Answer:

x = 4

Step-by-step explanation:

${x}^{2} = {(8 - x)}^{2}$

$= > {x}^{2} = {x}^{2} - 16x + 64$

$= > {x}^{2} - {x}^{2} + 16x = 64$

$= > 16x = 64$

$= > x = \frac{64}{16} = 4$

Answer 2

Step-by-step explanation:

(8 - x)² = x²

=> 8 - x = x or 8 - x = -x (rejected)

=> x = 4.