Question

Drag the missing statements and reasons to the correct spot to complete the proof

Answer 1

Answer:

The two column proof can be presented as follows;

1. $\overline{AB}$ ≅ $\overline{CD}$      ${}$               Given

2. $\overline{AD}$ ≅ $\overline{CB}$      ${}$              Given

3. $\overline{BD}$ ≅

4. ΔABD ≅ ΔBCD      ${}$     SSS

Step-by-step explanation:

Given that we have;

Segment $\overline{AB}$ of triangle ΔABD being congruent to the corresponding segment $\overline{CD}$ of triangle ΔBCD and segment $\overline{AD}$ of triangle ΔABD being congruent to the corresponding segment $\overline{CB}$ of triangle ΔBCD, and that the common segment $\overline{BD}$ of both triangles are congruent by reflexive property, we have that ΔABD is congruent to ΔBCD by the Side-Side-Side (SSS) rule of congruency.