Question

The density of a particular brand of corn syrup is known to be' 1360 g/L. If Ai-Lin determined the density to be 1372 g/L, then what is the percent error of Ai-Lin's experiment

Answer 1

Answer:  0.87%

Step-by-step explanation:

Percent error = $\dfrac{|\text{ Estimated value - actual value}|}{\text{actual value}}\times100$

Given: Estimated density =  1360 g/L

Actual value = 1372 g/L

Percent error = $\dfrac{|1360-1372|}{1372}\times100$

$\dfrac{|-12|}{1372}\times100\%\\\\= \dfrac{12}{1372}\times100\approx0.87\%$

Hence, the percent error of Ai-Lin's experiment = 0.87%