Respuesta :

Answer:

[tex]B.\angle PQS=70[/tex]

Step-by-step explanation:

[tex]We\ are\ given\ that,\\QS\ is\ the\ angle\ bisector\ of\ \angle PQR\\\angle PQR=140\\Hence,\\QS\ bisects\ \angle PQR\ into\ \angle PQS\ and\ \angle SQR\ which\ are\ both\ equal.\\Hence,\\\angle PQS\ = \angle SQR\\As\ \angle PQR=\angle PQS\ + \angle SQR\\140=\angle PQS\ + \angle SQR\\As\ \angle PQS\ = \angle SQR [Proven]\\140=\angle PQS\ + \angle PQS\\Hence,\\140=2\angle PQS\\\angle PQS=\frac{140}{2} \\\angle PQS=70[/tex]

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