Question

Question
Two bicycles have the following equations of motion, what is the distance between the bicycles at t = 0?
X1= -6.0 m+ (7.5 m/s)
X2 = 9.6 m +(-4.5 m/s)t​

Answer 1

Answer:

15.6 m

Explanation:

I'm pretty sure that there is supposed to be a t to the right of the (7.5 m/s).

If we substitute t with 0 (s), we get X1 = -6.0 m and X2 = 9.6 m.

The distance between the bicycles is X2-X1.

9.6 m -(-6.0 m)

= 9.6 m + 6.0 m

= 15.6 m

Hope this helps!