Question

a force F=600 N applied by a man on box and moves a distance d = 5m find the net work done on the box if the floor exerts a constant friction force of 20N

Answer 1

Answer:

Net work done = 2900 J

Explanation:

            Net force acting on box = f =  600N - 20N = 580N

             Work done = force applied x distance moved

                                        W = f x d

                                    W = 580N x 5m

                                        = 2900 J

Hope this helps!