Question

how fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5 j


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Answer 1

Explanation:

$kinetic \: energy= \frac{1}{2} m {v}^{2}$

$2 \times {10}^{5} = \frac{1}{2} 1000 {v}^{2}$

$2 \times {10}^{5} = 500 {v}^{2}$

$\frac{2 \times {10}^{5} }{500} = {v}^{2}$

${v}^{2} = 400$

$v = 20$

Answer 2

Answer:

KE= 1/2mv^2

where KE= 2.0*10^5j