Question

A bicyclist is riding at a tangential speed of 13.2 m/s around a circular track. The magnitude of the centripetal force is 377 N, and the combined mass of the bicycle and rider is 86.5 kg. What is the track's radius?​

Answer 1

Answer:

40m approximately

Explanation:

Given

Force =377N

Mass =86.5kg

Velocity =13.2m/s

Required

Radius of the track

The expression for the centripetal force acting on the cyclist is

F=mv²/r

Make r subject of the formula

r= mv²/F

Substitute

r=86.5*13.2²/377

r= 15,071.76/377

r=39.97

r=40m approximately

Answer 2

The radius of track will be "40 m".

Given:

Force,

• F = 377 N

Mass,

• m = 86.5 kg

Velocity,

• v = 13.2 m/s

As we know the formula,

→ $F = \frac{mv^2}{r}$

or,

→ $r = \frac{mv^2}{F}$

By substituting the values, we get

     $= \frac{86.5\times 13.2^2}{377}$

     $= \frac{15071.76}{377}$

     $= 39.97$

or,

     $= 40 \ m$

Thus the above answer is right.

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