Question

The sum of 3consecutive numbers is 48.find the numbers
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Answer 1

Answer:

15,16,17

Step-by-step explanation:

let the first number be x

second Be x+1

third be x+2

x+x+1+x+2=48

3x+3=48

3x=48-3

3x=45

x=45÷3

x=15

Answer 2

Step-by-step explanation:

Need to FinD :

• We have to find the numbers.

$\red{\frak{Given}} \begin{cases} & \sf {The\ sum\ of\ three\ consecutive\ number\ is\ {\pmb{\sf{48}}}.} \end{cases}$

We know that,

• The sum of the three consecutive numbers is 48. And we have to find the numbers.

So, let us consider the three consecutive numbers be x, x + 1, and x + 2. Now, let's find the numbers.

$\rule{200}{3}$

$\sf \dashrightarrow {x\ +\ x\ +\ 1\ +\ x\ +\ 2\ =\ 48} \\ \\ \\ \sf \dashrightarrow {3x\ +\ 3\ =\ 48} \\ \\ \\ \sf \dashrightarrow {3x\ =\ 48\ -\ 3} \\ \\ \\ \sf \dashrightarrow {3x\ =\ 45} \\ \\ \\ \sf \dashrightarrow {x\ =\ \dfrac{\cancel{45}}{\cancel{3}}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{x\ =\ 15.}}}}_{\sf \blue{\tiny{Value\ of\ x}}}}$

∴ Since, we considered the first number be x. Hence, the first number is 15.

$\rule{200}{3}$

Second NumbeR :

• x + 1
• 15 + 1
• 16

∴ Hence, the second number is 16.

$\rule{200}{3}$

Third NumbeR :

• x + 2
• 15 + 2
• 17

∴ Hence, the third number is 17.