Answer:
Vince walked 36 km on the 1st day of the trip.
Step-by-step explanation:
- Vince went on a 3-day hike trip.
- It is stated that Vince walks 3/4 of the distance that he walks the day before.
- His total traveled distance = 83.25
- Let 'x' be the distance traveled on the first day.
As he walks 3/4 of the distance that he walks the day before.
- so the second-day traveling distance = 3/4x
- And the third-day traveling distance = 3/4 × 3/4x
= 9/16x
Given his total traveled distance = 83.25
Therefore, the equation becomes
[tex]x\:+\:\frac{3}{4}x\:+\:\frac{9}{16}x\:\:=\:83.25[/tex]
Multiply both sides the 16 (L.C.M)
[tex]x\cdot \:16+\frac{3}{4}x\cdot \:16+\frac{9}{16}x\cdot \:16=83.25\cdot \:16[/tex]
simplify
[tex]16x+12x+9x=1332[/tex]
[tex]37x=1332[/tex]
Divide both sides by 37
[tex]\frac{37x}{37}=\frac{1332}{37}[/tex]
[tex]x=36[/tex] km
Therefore, Vince walked 36 km on the 1st day of the trip.
