Question

What is the average rate of change of h over the interval [-3,2]?
Give an exact number.

Answer 1

Answer:

$Average\ Rate = -0.4$

Step-by-step explanation:

Given: The table

Required: Determine the average rate of change over [-3,2]

This is calculated as:

$Average\ Rate = \frac{h(b) - h(a)}{b - a}$

In this case:

b = 2 and a = -3

So, we have:

$Average\ Rate = \frac{h(2) - h(-3)}{2 - (-3)}$

$Average\ Rate = \frac{h(2) - h(-3)}{2+3}$

$Average\ Rate = \frac{h(2) - h(-3)}{5}$

From the table:

$h(2) = 0$

$h(-3) = 2$

Substitute these values in the above expression:

$Average\ Rate = \frac{h(2) - h(-3)}{5}$

$Average\ Rate = \frac{0 - 2}{5}$

$Average\ Rate = \frac{-2}{5}$

$Average\ Rate = -0.4$