Answer: 17.2 g
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
[tex]\text{Moles of} HgS=\frac{20.0 g}{233g/mol}=0.085moles[/tex]
The balanced chemical equation is:
[tex]4HgS(s)+4CaO(s)\rightarrow 4Hg(l)+3CaS(s))+CaSO_4(s)[/tex]
According to stoichiometry :
4 moles of [tex]HgS[/tex] produce = 4 moles of [tex]Hg[/tex]
Thus 0.085 moles of [tex]HgS[/tex] will require=[tex]\frac{4}{4}\times 0.085=0.085moles[/tex] of [tex]Hg[/tex]
Mass of [tex]Hg=moles\times {\text {Molar mass}}=0.085moles\times 200.6g/mol=17.2g[/tex]
Thus 17.2 g of [tex]Hg[/tex] will be produced form 20.0 g of HgS.
