Question

What are the end behaviors of f(x)=-2(x-2)^5

Answer 1

Since this is an odd power function with a negative leading coefficient, as x approaches infinity y approaches negative infinity and as x approaches negative infinity y approaches positive infinity.

Answer 2

Answer:  Then, the end behavior of f(x) would be

f(x) → ∞ as x → - ∞ and, f(x) → -∞ as x → +∞

Step-by-step explanation:

Since we have given that

$f(x)=-2(x-2)^5$

Since the degree of polynomial is 5 , which is odd.

And the leading coefficient is -2, which is negative.

Then, the end behavior of f(x) would be

f(x) → ∞ as x → - ∞

and,

f(x) → -∞ as x → +∞