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19-12-2020
Chemistry

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What is the approximate energy of a photon having a frequency of 4X10^14 Hz? (h= 6.6X10-34 Js)

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19-12-2020

Answer:

2.65 x 10⁻¹⁹ J

Explanation:

ΔE = h·f = (6.63 x 10⁻³⁴J·s)(4 x 10¹⁴s⁻¹) = 2.65 x 10⁻¹⁹ J

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