Question

The product of sin 30 degrees and sin 60 degrees is the same as the product of

Answer 1

the cosine 30 and 60 degrees.

Answer 2

Answer:

$sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)$

Step-by-step explanation:

we know that

$sin(\alpha)=cos(\beta)$

when

$\alpha+\beta=90\°$ -------> complementary angles

so

$sin(30\°)=cos(60\°)$

$sin(60\°)=cos(30\°)$

Because

$30\°+60\°=90\°$ -------> complementary angles

In this problem the product of

$sin(30\°)*sin(60\°)$

is equal to

$cos(60\°)*cos(30\°)$

therefore

$sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)$