We will divide the area of the figure into two smaller figures and then add up their values.
Firstly, the triangle with base 9, height 12 and hipotenuse 15. The area of a triangule is base times height divided by two. So,
[tex]A_1= \frac{12\times9}{2} = 54[/tex]
And the second figure we'll consider is the trapezium with larger base 15, smaller base 10 and height 3. The area of a trapezium is given by the sum of the bases times the height divided by two. So,
[tex]A_2=\frac{3\times(15+10)}{2} = 37.5[/tex]
Therefore the total area is:
[tex]A=A_1+A_2\\A=37.5 + 54\\A=91.5\text{ units}^2[/tex]
