Respuesta :
Answer:
25 atoms
Explanation:
Given data:
Total number of atoms = 400 atom
Atoms remain after 4 half lives passed = ?
Solution:
At time zero = 400 atom
At first half life = 400 atom/2 = 200 atom
At 2nd half life = 200 atom/2 = 100 atom
At 3rd half life = 100 atom/2 = 50 atom
At 4th half life = 50 atom/2 = 25 atom
Thus, 25 atoms are remained after 4 half lives.
25 atoms of the radioactive atoms will remain after 4 half lives.
Given in the question,
- Initial amount of a radioactive element = 400 atoms
- Number of half lives = 4
Expression for the amount remaining of a radioactive element after 'n' half lives is given by,
[tex]N=N_0(\frac{1}{2})^n[/tex]
Here, [tex]N_0=[/tex] Initial amount
[tex]n=[/tex] Number of half lives
By substituting the vales of [tex]N_0[/tex] and [tex]n[/tex] in the question,
[tex]N=400(\frac{1}{2})^4[/tex]
[tex]=\frac{400}{16}[/tex]
[tex]=25[/tex]
Therefore, 25 atoms of the radioactive atoms will remain after 4 half lives.
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