Question

let f (x)=x^2 + 6 and g (x) =x+8/x find (g o f) (-7)

a) 384 /7
b) -57/7
c) 295 /49
d) 63/55
its not C i got that one wrong

any help would be appreciated thank you

Answer 1

i hope this helps you

Answer 2

The value of g(f(-7)) is 63/55 and this can be determined by using the given data and the function properties.

Given :

• $\rm f(x) = x^2+6$

• $\rm g(x) = \dfrac{x+8}{x}$

First, determine the value of f(-7).

$\rm f(-7) = (-7)^2+6$

f(-7) = 49 + 6

f(-7) = 55

Now, the expression of g(f(x)) is given by:

$\rm g(f(x)) = \dfrac{x^2+6+8}{x^2+6}$

$\rm g(f(x)) = \dfrac{x^2+14}{x^2+6}$

Now, substitute the value of (x = -7) in the above expression.

$\rm g(f(x)) = \dfrac{(-7)^2+14}{(-7)^2+6}$

$\rm g(f(x)) = \dfrac{49+14}{49+6}$

$\rm g(f(x)) = \dfrac{63}{55}$

The value of g(f(-7)) is 63/55 and this can be determined by using the given data and the function properties. Therefore, the correct option is d).

For more information, refer to the link given below:

https://brainly.com/question/21114745