Question

A cannonball with a perfect horizontal velocity of 50.0 m/s flies 350 m before hitting the
ground. How much time was the cannonball in the air? Remember t d/v
05s
O 10s
35 s
7s

Answer 1

Answer:

7 s

Explanation:

The time taken can be found by using the formula

$t = \frac{d}{v}$

d is the distance

v is the velocity

From the question we have

$t = \frac{350}{50} = \frac{35}{5} = 7$

We have the final answer as

7 s

Hope this helps you