Question

Which function is equivalent to g (k) = -k'+ 6k-9?
a g(k) = -(k- 3)
g(k) = (-k+ 3)(k+ 3)
© g(k) =-(k+3)
O
g(k) = (-k- 3)(–k+ 3)

Answer 1

I believe it’s g(k)=(-k- 3)(-k+3)

Answer 2

Answer:

I believe it’s g(k)=(-k- 3)(-k+3)

Step-by-step explanation: