Respuesta :

n+2 and n+4.n+4 given that their sum is 81
The integers are 25,27,29
Explanation:
let n = the first integer
let n+ 2 = the second integer
let n+ 4 = the third integer
Then add them and set the three integers equal to 81.
n+n+2+n+4=81
3n+6=81
3n+6-6=81-6
3n=75
3n/3=75/3
n=25

The first integer is 25
The second integer is 27
the third integer is 29
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