Respuesta :

Answer:

a(5)=8

Step-by-step explanation:

it is geometric  so we will use this equation:

a(n)=a1*(r)^(n-1)

and we have a(1)=128 , r=1/2    

So a(n)=128*(1/2)^(n-1)

fifth term : a(5)=128*(1/2)^(5-1)=8

hope this helps

[tex]8[/tex]

A geometric series is the sum of an unlimited number of terms with a fixed ratio between them.

If [tex]a,r[/tex] denote first term and common ratio respectively, then the[tex]n^{th}[/tex] term is given by [tex]ar^{n-1}[/tex]

Put [tex]a=128[/tex]

Put [tex]r=\frac{1}{2}[/tex]

Put [tex]n=5[/tex]

Therefore,

[tex]a_5=128(\frac{1}{2})^{5-1}[/tex]

   [tex]=\frac{128}{16}\\\\ =\boldsymbol{8}[/tex]

So, the fifth term is [tex]\boldsymbol{8}[/tex]

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