Respuesta :
Answer:
a(5)=8
Step-by-step explanation:
it is geometric so we will use this equation:
a(n)=a1*(r)^(n-1)
and we have a(1)=128 , r=1/2
So a(n)=128*(1/2)^(n-1)
fifth term : a(5)=128*(1/2)^(5-1)=8
hope this helps
[tex]8[/tex]
A geometric series is the sum of an unlimited number of terms with a fixed ratio between them.
If [tex]a,r[/tex] denote first term and common ratio respectively, then the[tex]n^{th}[/tex] term is given by [tex]ar^{n-1}[/tex]
Put [tex]a=128[/tex]
Put [tex]r=\frac{1}{2}[/tex]
Put [tex]n=5[/tex]
Therefore,
[tex]a_5=128(\frac{1}{2})^{5-1}[/tex]
[tex]=\frac{128}{16}\\\\ =\boldsymbol{8}[/tex]
So, the fifth term is [tex]\boldsymbol{8}[/tex]
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https://brainly.com/question/4617980?referrer=searchResults