I need some serious help with some problems there are some on my profile and this one

Answer:
a) 28
b) D
Step-by-step explanation:
a) As you can see from the diagram, in a 60-30 right triangle, the side adjacent to the 60° angle is half of the hypotenuse.
14*2=28
b) If you remember your SohCahToa, then you'll know that your trigonometric functions are:
[tex]sin = \frac{opp}{hyp}\\cos = \frac{adj}{hyp}\\tan = \frac{sin}{cos}[/tex]
Now we can check each one to find the incorrect ratio:
[tex]sin (30^o)=\frac{4}{8}=\frac{4}{8}\\cos(60^o)=\frac{4}{8}=\frac{4}{8}\\sin(60^o)=\frac{\sqrt{48}}{8}=\frac{\sqrt{48}}{8}\\tan(30^o)=\frac{4}{\sqrt{48}}\neq \frac{\sqrt{48}}{8}[/tex]