Answer:
The standard error of the mean remains unchanged.
Step-by-step explanation:
Given that:
The standard error (S.E) of the mean [tex]= \dfrac{\sigma}{\sqrt{n}}[/tex] with is independent of confidence coefficient.
The margin of error [tex]E = z \times S.E[/tex]
This explains the claim that as the confidence coefficient reduces, the z-value also reduces, so as the Margin of error (E) but the standard error will always remain unchanged.
i.e.
From the question;
sample size n = 100
standard deviation = 1
mean = 3.0
The standard error (S.E) of the mean [tex]= \dfrac{1}{\sqrt{100}}[/tex]
= 0.1
So, if the confidence coefficient is reduced to 0.80, the standard error of the mean remains unchanged.