Question

Can someone help me and make a code for this in PYTHON, please? I would be very grateful!
It is estimated that China on July 1, 2019. had 1,420,062,022 inhabitants. The population of China increases by 0.35% every year. Assuming that the annual population growth in China will not change, show the expected population of China in the next ten years.
Please... Thanks in advance!

Answer 1

Code:

next_ten_years = 1420062022*1.0035**10

print(next_ten_years)

Output:

1470554353.1178253

Explanation:

Since the population of inhabitants increases by $0.35\%$ each year, the total population must be $100.35\%$ of the previous year's population (since it includes the previous size of the population and the $0.35\%$ increase of the population)

The math:

Expected population in next 10 years = $1420062022 \times 1.0035^{10}$  ($100.35\%$ is $1.0035$)

Code:

Looking at the code above, the '**' raises the power of a number to the number you put after the operator, so 1.0035**10  is $1.0035^{10}$. The '*' operator multiplies the two numbers that are placed before and after the operator, so 1420062022*1.0035 is $1420062022\times 1.0035$.

The expected population in the next ten years is 1,470,554,353 (if we round to the nearest inhabitants since there can't be a decimal amount of inhabitants).

Hope this helps :)