Question

Solve Fully and send full answer with calculations....
Correct Answer Only.......I will be marking the correct answer as brainliest.....​
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Answer 1

Given

• There are four 4Ω resistors
• Potential Difference = 2V

To Find

• Current when the key is open
• Current when the key is closed

Solution

● V = IR [Ohm's law]

● Rₙₑₜ = R₁ + R₂ ..... + Rₙ [Series Connection]

● 1/Rₙₑₜ = 1/R₁ + 1/R₂ ..... + 1/Rₙ

[Parallel Connection]

✭ Series Connection :

Both these connection are separated into two series and parallel connection. First two 4 Ω resistance in series and these are connected in parallel

→ R(eq) = R₁ + R₂ ..... + Rₙ

→ R(eq) = 4 + 4

→ R(eq) = 8 Ω

✭ Parallel Connection :

• R₁ = 8Ω
• R₂ = 8Ω

→ 1/Rₙₑₜ = 1/R₁ + 1/R₂ ..... + 1/Rₙ

→ 1/Rₙₑₜ = 1/8 + 1/8

→ 1/Rₙₑₜ = (1+1)/8

→ 1/Rₙₑₜ = 2/8

→ Rₙₑₜ = 8/2

→ Rₙₑₜ = 4Ω

✭ Current when the key is closed :

→ V = IR

→ 2 = I × 4

→ 2/4 = I

→ Current = 0.5 A

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When the key is open then there would be no current, that is Current = 0 A