Find cos(a) in the triangle.
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Answer:
cos(α) = 24/25.
Step-by-step explanation:
First of all, we'll find the answer just using the fact that ABC is a right triangle in C. So, by the definition of cosine:
[tex]\cos(\alpha) = \dfrac{AC}{AB}\\\\\boxed{\cos(\alpha) = \dfrac{24}{25}}[/tex]
Now, we'll solve the question with another approach. By the Law of Cosines in the triangle ABC:
[tex]BC^2 = AB^2+AC^2-2\cdot AB\cdot AC\cos(\alpha)\\\\7^2 = 25^2+24^2-2\cdot 25\cdot 24\cos(\alpha)\\\\49 = 625+576-1200\cos(\alpha)\\\\1200\cos(\alpha)=1152\\\\\boxed{\cos(\alpha) = \dfrac{24}{25}}[/tex]