Question

PLEASE HELP !!! WILL GIVE BRAINLIEST! How does changing the base number (inside the parentheses) change your graph?

Answer 1

For the equation you gave, which is y = a(b)^x, increasing the b value would increase how much more the y value would increase/decrease (depending if x is > or < 0). Please view the image attached!

Answer 2

On changing the base number (inside the parentheses), for $f(y)=a(b)^x$, for any positive integer added to parentheses the graph will lean toward the y-axis in the first quadrant where the graph will pass through a. while, for any negative integer added to parentheses the graph is not possible.

How does changing the base number (inside the parentheses) change your graph for $f(y)=a(b)^x$?

Given to us,  $f(y)=a(b)^x$;

If we try to draw $f(y)=a(b)^x$ on a graph with value a=b=1, the graph will be a straight line parallel to x-axis passing through (0,1), where the value on y-axis changes with a value. (green line)

Also, If we draw $f(y)=a(b+3)^x$ on a graph with value a=b=1, the graph will be a exponential line parallel to x-axis passing through (0,1). (black line)

{$y= p(q+3)^x$; p=a , y=b}}

But,  If we draw $f(y)=a(b-3)^x$ on a graph with value a=b=1, the graph will not be displayed because it is not possible.

{$y= s(t-3)^x$; s=a , t=b}}

Hence, on changing the base number (inside the parentheses), for $f(y)=a(b)^x$, for any positive integer added to parentheses the graph will lean toward the y-axis in the first quadrant where the graph will pass through a. while, for any negative integer added to parentheses the graph is not possible.

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https://brainly.com/question/1699227