Write the standard form of the equation of the line that passes through (-2, -3) and (2,-5).

By standard form, I'm assuming you mean slope-intercept form, which is y=mx+b. First, we need to find m, or the slope. To do this, we need to plug it into this equation: m= y2-y1/x2-x1. We can rewrite this with our two points, so we make it into m= -5+3/2+2. I did plus signs because if you subtract a negative number from a number, it has the same effect as addition does. Now, we have m= -2/4, which we can simplify to -1/2. Now, we have y=-1/2x+?. Now, let's plug in the numbers in slope-intercept form. I'll choose the ordered pair (-2, -3) for this example. Now that I've plugged the numbers in y=mx+b form (slope-intercept form), we have -3=(-1/2⋅-2)+b. Now, we solve it. First, we do the problem in the parenthesis, from that, we get 1. Now, we have -3=1+b, let's subtract 1 from both sides. Now, we have -4=b. That means our y-intercept is -4. Let's plug this back in the equation. We get y=-1/2x-4. I hope this helps!