The voltage drop across the 30Ω resistor in the given circuit is 60V which is described below.
Ohm's Law:
According to the circuit given in the question, all the resistors are connected in series with the battery.
The equivalent resistance R in the circuit is:
R = 10Ω + 20Ω + 30Ω
R = 60Ω
The battery has a voltage of V = 120V
From Ohm's Law:
V = IR
where I is the current in the circuit
120 = I × 60
I = 2A
So, the same current flows through all the resistors as they are connected in series.
The voltage drop across 30Ω resistor is:
V₃₀ = 2×30
V₃₀ = 60 V
Learn more about Ohm's Law:
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