What is the voltage drop across the 30 ohm resistor?

The voltage drop across the 30Ω resistor in the given circuit is 60V which is described below.
According to the circuit given in the question, all the resistors are connected in series with the battery.
The equivalent resistance R in the circuit is:
R = 10Ω + 20Ω + 30Ω
R = 60Ω
The battery has a voltage of V = 120V
From Ohm's Law:
V = IR
where I is the current in the circuit
120 = I × 60
I = 2A
So, the same current flows through all the resistors as they are connected in series.
The voltage drop across 30Ω resistor is:
V₃₀ = 2×30
V₃₀ = 60 V
Learn more about Ohm's Law:
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