First you find the integral by using the property the integral of x^n (where n is a number) =(x^(n+1))/(n+1)
So in this case:
abs(x-5)=x^n (where n=1) - 5x^m (where m=0)
so when you solve for it, you get
=abs( [(x^(1+1))/ (1+1)] - [5(x^(0+1))/(0+1)] ) from 0 to 10
= abs( .5x^2 -5x) from 0 to 10
then plug in the top value, x=10, and subtract the bottom value, x=0, from it:
=abs( .5(10^2) -5(10)) - abs(.5(0)-5(0))
=0 - 0
=0
